How does

$\displaystyle 1 - \frac{8}{x^3} = \frac{x^3-8}{x^3}$ ?

Pretty rusty..

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- Mar 28th 2011, 01:26 PMkwiknessFractional Equality
How does

$\displaystyle 1 - \frac{8}{x^3} = \frac{x^3-8}{x^3}$ ?

Pretty rusty.. - Mar 28th 2011, 01:27 PMe^(i*pi)
$\displaystyle 1 = \dfrac{x^3}{x^3}$

Now they have the same denominator you can subtract - Mar 28th 2011, 01:28 PMkwikness
Thanks