Originally Posted by
Drdj If (2,1) is a solution fo the simultaneous equations,
x^2 + xy + ay = b
2ax + 3y = b
A) Find the value of a and of b. [a=1, b =7]
B) Find also the other solution [x=-7 and y = 7)
I have solved both parts, but I face a problem.
After part a), I substituted values of a and b into the equation to obtain
x^2 + xy + y = 7 and 2x + 3y = 7
Substituting x = (7-3y)/2 into the equation x^2 + xy + y = 7
I obtain the quadratic expression y^2 - 9y + 14 = 0
Hence, I get y = 7 and y =2 ; x = -7 and x = 1/2
Why do I reject y =2 and x = 1/2 combination ?
I know that substituting the above into 2x + 3y = 7 satisfies the equation
But it doesn't satisfy x^2 + xy + y = 7. How would I know?
Thanks