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Math Help - Maximum/Minimum value of a quadratic expression

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    Exclamation Maximum/Minimum value of a quadratic expression

    State the minimum or maximum value of y and the corresponding value of x for
    y=4(x^2) + 2 .
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    4> 0\Rightarrow \displaystyle f:\mathbb{R} \mapsto \mathbb{R}, f(x)=4x^{2}+2 has a minimum, it is obtained for x=-\frac{0}{2\cdot4 }=0, y=\frac{-\Delta }{4\cdot4}=2
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  3. #3
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    Quote Originally Posted by Ilsa View Post
    State the minimum or maximum value of y and the corresponding value of x for
    y=4(x^2) + 2 .
    y = 4(x - 0)^2 + 2

    compare your equation to the vertex form of a quadratic equation ...

    y = a(x - h)^2 + k

    where the vertex is the point (h,k)

    since a > 0 , x = h is the vertex location and y = k is the corresponding minimum value
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