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Math Help - new inequality

  1. #1
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    new inequality

     <br /> <br />
\begin{array}{l}<br />
 solve\;the\;inequality\;in\;R \\ <br />
 (x + 3)^n (x - 2) \prec 0 \\ <br />
 n\;is\;natural\;number \\ <br />
 \end{array}<br /> <br /> <br />
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  2. #2
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    Case 1: \displaystyle (x + 3)^n > 0 and \displaystyle (x - 2) < 0.

    See what you can do here.


    Case 2: \displaystyle (x + 3)^n < 0 and \displaystyle (x - 2) > 0.

    See what you can do here.
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