Math Help - new inequality

1. new inequality

$

\begin{array}{l}
solve\;the\;inequality\;in\;R \\
(x + 3)^n (x - 2) \prec 0 \\
n\;is\;natural\;number \\
\end{array}

$

2. Case 1: $\displaystyle (x + 3)^n > 0$ and $\displaystyle (x - 2) < 0$.

See what you can do here.

Case 2: $\displaystyle (x + 3)^n < 0$ and $\displaystyle (x - 2) > 0$.

See what you can do here.