$\displaystyle \begin{array}{l} solve\;the\;inequality\;in\;R \\ (x + 3)^n (x - 2) \prec 0 \\ n\;is\;natural\;number \\ \end{array} $
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Case 1: $\displaystyle \displaystyle (x + 3)^n > 0$ and $\displaystyle \displaystyle (x - 2) < 0$. See what you can do here. Case 2: $\displaystyle \displaystyle (x + 3)^n < 0$ and $\displaystyle \displaystyle (x - 2) > 0$. See what you can do here.
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