Thread: Simultaneous equations

Solve for a, b and c given that:

• 2a+4b+5c= 2

• 5a+3b-2c= 13

• 3a-2b-3c= 0

Originally Posted by oldschool999

Solve for a, b and c given that:

• 2a+4b+5c= 2

• 5a+3b-2c= 13

• 3a-2b-3c= 0

One way is called the substitution method. Pick any one of the equations, say the bottom one, and solve it for one of the variables:




Insert this value of c into the other two equations:




So now we need to solve:




Solve one of these for one of the other unknowns, etc.

For verification I get that

-Dan

Originally Posted by oldschool999

Solve for a, b and c given that:

• 2a+4b+5c= 2

• 5a+3b-2c= 13

• 3a-2b-3c= 0

What methods have you been shown?

RonL