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Math Help - Dividing polynomial

  1. #1
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    Dividing polynomial

    I'm having problems dividing the polynomial 2x^5 + 2x^3 + x^2 + 1 by x^2 + 1
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  2. #2
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    Looks straight forward to me. But I don't know what to tell you without seeing what you did. Did you remember to include "0x" in the divisor and " 0x^4" and " 0x" in the dividend? How many times does x^2 divide into 2x^5?
    Last edited by HallsofIvy; March 23rd 2011 at 05:49 AM.
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  3. #3
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    It goes in 2x^3 times but I get x^2 as the next quotient part but the correct quotient should be 2x^3 - 1 according to the answer the book gives
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  4. #4
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    x^2+0x+1sqrt(2x^5+0x^4+2x^3+x^2+0x+1)

    This is the subtracting parts: The quotient i got is 2x^3+x^2+x+1

    Part 1 2x^5+0x^4+2x^3

    Part 2 x^4+x^2

    x^4+x^3+x^2

    Part 3 x^3+0x

    x^3+x^2+x

    Part 4 x^2+1

    x^2+x+1

    Final x
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  5. #5
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    Yes, x^2 divides into 2x^5 2x^3 times. And multiplying the entire divisor by 2x^3 gives 2x^5+ 2x^3
    Now subtract that from the dividend:
    2x^5+ 2x^3+ x^2+ 1- (2x^5+ 2x^3)= x^2+ 1.

    And now, of course, x^2+ 1 divides into that exactly once: the quotient is 2x^3+ 1.
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