# Math Help - solving a system

1. ## solving a system

Hi, Im really confused on one of the problems that I have for homework.
Solve the system:
x^2 + 2y^2 =33
x^2 + y^2 + 2x =19

Thanks!

2. Multiply the bottom equation by 2. Subtract the bottom from the top and you should get a quadratic which you can solve.

3. okay, i did it out and got -1 + square route of six, and -1 - square route of six. Did i do it right?

4. $x^2 + 2y^2 =33$
$2x^2+2y^2+4x=38$

$-x^2-4x+5=0$

$x^2+4x-5=0$

$(x+5)(x-1)=0$

take it from there.

5. ohhh ok thanks i get it now i did some stupid multiplication thing before

6. Be sure you finish the problem! The reason rtblue said "take it from there" is that a solution is a pair of numbers, x and y. This problem has four separate solutions.