The "inverse" of log (base 10) is 10 to a power. Write that as log(c)= -2.2 and take .

100= 10^2 so that log(100)= 2.If the molar concentration in a liquid is multiplied by 100, the pH will be reduced by 2. Explain why (something to do with logarithmic rules).

That's the same as or2) f(x)= 225.027* x^ -0.5

- What is x when f(x) is 10.000?

Do you mean y= f(x)? 10.000 decreased by 5% will be 9.500. Solve the same equation with 9.5 instead of 10 to get the new value of x. The percentage increase will be "(new x- old x)/old x.- By which percent-rate will x increase if y decreases with 5 %

NO, it is just 1/sqrt(0.5). The negative power puts the square root in the denominator but does not change a sign.[Now they're not that difficult, but I think the reason I can't seem to solve them is because I'm not sure if the reverse function of a negative power in this case x^-0.5, is 1/sqr(-0.5).

When I try to isolate x, it certainly doesn't work to use 1/sqr(-0.5) in the process. Nor does it help when I try to use it to calculate the percent rate increase in x, for which the formula is: 1+ry= (1+rx)^a, rx= percent rate for x, ry= percent rate for y.

Please help ASAP!

Thank you in advance.