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Math Help - (6)/(x^2 - 3x) - (5)/(2)(3-x)

  1. #1
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    (6)/(x^2 - 3x) - (5)/(2)(3-x)

    Hi guys, need help on this question

    My working:
    (6)/(x^2-3x) - (5)/(2)(3-x) = (6)/(x)(x-3) - (5)/(2)(3-x)
    = - (6)/(x)(3-x) - (5)/(2)(3-x)
    = -6(-2)-5(-x)/2x(3-x)
    = (12+5x)/(2x)(3-x)

    Answer = (5x+12)/(2x)(x-3)

    What is wrong with my working?

    P.S sorry that it's a bit messy, I don't know how to make it into that "mathematics" form.
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  2. #2
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    \dfrac{6}{x^2-3x}-\dfrac{5}{3-x}=\dfrac{6}{x(x-3)}+\dfrac{5}{2(x-3)}
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  3. #3
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    Quote Originally Posted by Plato View Post
    \dfrac{6}{x^2-3x}-\dfrac{5}{3-x}=\dfrac{6}{x(x-3)}+\dfrac{5}{2(x-3)}
    Edited: Thanks a lot Plato, I knew what went wrong

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