# Thread: (6)/(x^2 - 3x) - (5)/(2)(3-x)

1. ## (6)/(x^2 - 3x) - (5)/(2)(3-x)

Hi guys, need help on this question

My working:
(6)/(x^2-3x) - (5)/(2)(3-x) = (6)/(x)(x-3) - (5)/(2)(3-x)
= - (6)/(x)(3-x) - (5)/(2)(3-x)
= -6(-2)-5(-x)/2x(3-x)
= (12+5x)/(2x)(3-x)

What is wrong with my working?

P.S sorry that it's a bit messy, I don't know how to make it into that "mathematics" form.

2. $\dfrac{6}{x^2-3x}-\dfrac{5}{3-x}=\dfrac{6}{x(x-3)}+\dfrac{5}{2(x-3)}$

3. Originally Posted by Plato
$\dfrac{6}{x^2-3x}-\dfrac{5}{3-x}=\dfrac{6}{x(x-3)}+\dfrac{5}{2(x-3)}$
Edited: Thanks a lot Plato, I knew what went wrong