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Thread: quadratic equations

  1. #1
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    quadratic equations

    Hello, an exercise require to simplify this equation but i don't know what they are, could you help me? thank you!

    \left\frac{a^2+4a\sqrt3+12}{2a^2+3a\sqrt3-6}
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  2. #2
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    (a+ b)(a+ c)= a^2+ (b+c)x+ bc
    so to factor x^2+ 4a\sqrt{3}+ 12
    you are looking for two numbers that add to 4\sqrt{3} and multiply to 12. 2\sqr{3} and 2\sqrt{3} work!

    To factor 2a^2+ 3a\sqrt{3}- 6, try (a- 2\sqrt{3})(ba+ c)=  ba^2+(b- 2\sqrt{3}c)a- 2c\sqrt{3}= 2a^2+ 3a\sqrt{3}- 6 and compare coefficients.
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  3. #3
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    how to find quick the two numbers?
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  4. #4
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    Quote Originally Posted by scientifico View Post
    Hello, an exercise require to simplify this equation..
    \left\frac{a^2+4a\sqrt3+12}{2a^2+3a\sqrt3-6}
    That is NOT an equation; ALL equations have an equal sign.
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  5. #5
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    Quote Originally Posted by scientifico View Post
    how to find quick the two numbers?
    Practice.
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