# Math Help - quadratic equations

Hello, an exercise require to simplify this equation but i don't know what they are, could you help me? thank you!

$\left\frac{a^2+4a\sqrt3+12}{2a^2+3a\sqrt3-6}$

2. $(a+ b)(a+ c)= a^2+ (b+c)x+ bc$
so to factor $x^2+ 4a\sqrt{3}+ 12$
you are looking for two numbers that add to $4\sqrt{3}$ and multiply to 12. $2\sqr{3}$ and $2\sqrt{3}$ work!

To factor $2a^2+ 3a\sqrt{3}- 6$, try $(a- 2\sqrt{3})(ba+ c)= ba^2+(b- 2\sqrt{3}c)a- 2c\sqrt{3}= 2a^2+ 3a\sqrt{3}- 6$ and compare coefficients.

3. how to find quick the two numbers?

4. Originally Posted by scientifico
Hello, an exercise require to simplify this equation..
$\left\frac{a^2+4a\sqrt3+12}{2a^2+3a\sqrt3-6}$
That is NOT an equation; ALL equations have an equal sign.

5. Originally Posted by scientifico
how to find quick the two numbers?
Practice.