Plz help me: 4(x-2)/3>-6 First I add 6 to both sides so that I get: 4(x-2)+6/3>0 But what do I do then?
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Originally Posted by julieta Plz help me: 4(x-2)/3>-6 First I add 6 to both sides so that I get: 4(x-2)+6/3>0 But what do I do then? Well, the denominator is positive, so for the whole expression to be positive, then the numerator itself must be positive... so 4(x-2) + 6 > 0
Originally Posted by julieta Plz help me: 4(x-2)/3>-6 First I add 6 to both sides so that I get: 4(x-2)+6/3>0 <=== Should be 4(x-2)/3 + 6>0 But what do I do then? Hi julieta, No need to move the -6. Just multiply both sides by 3. $\displaystyle \dfrac{4(x-2)}{3}>-6$ $\displaystyle 4x-8>-18$ $\displaystyle 4x>-10$ $\displaystyle x>-\dfrac{5}{2}$
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