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Math Help - Inequality

  1. #1
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    Inequality

    Plz help me:

    4(x-2)/3>-6

    First I add 6 to both sides so that I get:

    4(x-2)+6/3>0

    But what do I do then?
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  2. #2
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    Quote Originally Posted by julieta View Post
    Plz help me:

    4(x-2)/3>-6

    First I add 6 to both sides so that I get:

    4(x-2)+6/3>0

    But what do I do then?
    Well, the denominator is positive, so for the whole expression to be positive, then the numerator itself must be positive... so

    4(x-2) + 6 > 0
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by julieta View Post
    Plz help me:

    4(x-2)/3>-6

    First I add 6 to both sides so that I get:

    4(x-2)+6/3>0 <=== Should be 4(x-2)/3 + 6>0

    But what do I do then?
    Hi julieta,

    No need to move the -6. Just multiply both sides by 3.

    \dfrac{4(x-2)}{3}>-6

    4x-8>-18

    4x>-10

    x>-\dfrac{5}{2}



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