1. ## Inequality

Plz help me:

4(x-2)/3>-6

First I add 6 to both sides so that I get:

4(x-2)+6/3>0

But what do I do then?

2. Originally Posted by julieta
Plz help me:

4(x-2)/3>-6

First I add 6 to both sides so that I get:

4(x-2)+6/3>0

But what do I do then?
Well, the denominator is positive, so for the whole expression to be positive, then the numerator itself must be positive... so

4(x-2) + 6 > 0

3. Originally Posted by julieta
Plz help me:

4(x-2)/3>-6

First I add 6 to both sides so that I get:

4(x-2)+6/3>0 <=== Should be 4(x-2)/3 + 6>0

But what do I do then?
Hi julieta,

No need to move the -6. Just multiply both sides by 3.

$\dfrac{4(x-2)}{3}>-6$

$4x-8>-18$

$4x>-10$

$x>-\dfrac{5}{2}$