solve 2x^2-5x+2=[5-sqrt(9+8x)]/4 where x<5/4
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$\displaystyle 2x^2-5x+2 = \dfrac{5-\sqrt{9+8x}}{4}$ $\displaystyle 8x^2-20x+8 = 5 - \sqrt{9+8x}$ $\displaystyle 8x^2 - 20x+3 = \sqrt{9+8x}$ Square and solve the horrible quartic for x discarding any extraneous solutions