Suppose Jane has 'x' cents and John has 'y' cents. Then first tell me, what can you say about the price of the book in terms of 'x' and 'y'?
Dear sir ,
I would appreciate if anyone can show me the solution to the below question.
Jane and John wish to buy a book. However, Jane needs seven more cents to buy the book, while John needs one more cent. They decide to buy only one book together but discover that they do not have enough money. What is the price of the book?
Jane needs 7 cents MORE so the price of the book is x+7. Again, John need 1 cent MORE, so the price of the book is y+1. Can you verify it now, by looking at the problem?
Suppose you have 10 cents in your hand, and you need 5 more cents to buy the book. What is the price of the book then?
You said ", Jane needs seven more cents to buy the book". What is 7 more than x?
"John needs one more cent". What is 1 more than y?
But I don't think you need to set up equations. When John and Jane put their money together, they still do not have enough money. Yet, John needed only one cent more. What does that tell you about how much money Jane had? And, therefore, what was the price of the book?
(These are not very realistic numbers!)
What you can say is that
Exactly! If John needed only one more cent to buy the book- and Jack and Jane together did not have enough money to buy it, then Jane has no money. That means that John has 6 cents and the book cost 7 cents.
But it doesn't seem right, because if they put their money together, they can buy the book.
Only way I see it is that if Jane has 0 cent.
(This is assuming integer pennies. If we allow "ha'pennies" then Jane could have one halfpenny so the book cost 6 and 1/2 pennies and John has 5 and a half pennies.)