# Thread: Worded algebra problem #2.

1. ## Worded algebra problem #2.

Dear Sir ,
I hope someone can help me in the below question.
Thanks
Kingman

Two old women started at sunrise and each walked at a constant velocity. One went from A to B and the other from B to A. They met at noon and, continuing with no stop, arrived respectively at B at 4 p.m. and at A 9 p.m. At what time was the sunrise on this day?

2. The two women started at the same time and walked with constant (but not the same) velocity. If sunrise was "x" hours before noon then the first woman walked for 4+ x hours and the second for x+ 9 hours. Let the distance from A to B be "d" km. The first womans speed was d/(x+ 4) km/hour and the second's d/(x+ 9).

They met at noon- x hours after starting. The first woman walked dx/(x+4) km in that time and the second woman walked dx/(x+9) km. Since they met at noon, the total distance walked was d km: $\displaystyle dx/(x+4)+ dx/(x+9)= d$ You can divide through by d to cancel it and have a single equation left to solve for x.

That's pretty good for two "old women"!

3. the hint is: 'use similar triangle' which i do not know how to start.