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Math Help - Basic algebra question

  1. #1
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    Basic algebra question

    I don't know what kind of algebra question this, hence the general title, but its easy, I just can't figure it out.

    here goes:


    15000(p-1.6) = 2000


    p = ?

    All help appreciated, thanks.



    edit: btw, there's a "times" between the 15000 and the bracket so its: 15000 times (p-1.6) = 2000 and solve for p.
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  2. #2
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    To Solve for p, you basically need to multiply the 15000 into the brackets to get:
    15000p - 24000 = 2000

    Can you solve this equation from here?
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  3. #3
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    Yeah got it. I don't know if my working is correct, but I took what you said and then I had:

    15000p - 24000 = 2000

    p - 24000 = 2000 / 15000

    2000/15000 = 0.133333333

    15000 x 0.133333333 = 2000

    therefore p = (1.6+0.133333333) = 1.7333


    again my working is probly wrong and wonky, but looks like I got the right answer ?
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  4. #4
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    Yes you got the right answer. However, you should always move all constants (in this case 2000 and 24000) to the side of the equation without the variable (in this case p) before you divide.

    Therefore you would get:
    15000p = 2000 + 24000
    15000p = 26000
    p = \frac{26000}{15000}

    Therefore p = 1.73333
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  5. #5
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    Sorry, but that is not correct.

    If you have expanded the brackets to get

    \displaystyle 15000p - 24000 = 2000

    the first thing you need to do is undo the \displaystyle -24000.

    So \displaystyle 15000p = 26000

    \displaystyle p = \frac{26000}{15000}

    \displaystyle p = \frac{26}{15}.


    The alternative way to do it would be to divide both sides by \displaystyle 15000, rather than expanding...

    \displaystyle 15000\left(p - \frac{8}{5}\right) = 2000

    \displaystyle p - \frac{8}{5} = \frac{2000}{15000}

    \displaystyle p - \frac{8}{5} = \frac{2}{15}

    \displaystyle p - \frac{24}{15} = \frac{2}{15}

    \displaystyle p = \frac{26}{15}, which is the same answer.
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  6. #6
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    Ok, I understand now how to solve it.

    Thanks.
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