Thread: equation solving

y + x^2 = 4x
y + 4x = 16

Hello, can someone please confirm which of my following answers would be the correct way to solve this problem.

i)
x = 4, y=0

ii)
x^2-8x+16=0

Equation ii is fine and (4,0) is the only pair of solutions so if i) is your answer then it's correct

x^2 - 8x + 16 factors into (x-4)^2, so i) and ii) would both work. =)

However, as an answer to the problem, only x= 4, y= 0 is correct.

The equation x^2- 8x+ 16= 0 is a step on the way to finding the solution.