Hi!

I have this task:

y=x^2-12x+36.36

Find all squares that has 2 points on this function and 2 points on the x axis.

I thought this task with using simply y=x^2

To find at which point there is a square I thought a simple equation: 2x=y ; 2x=x^2

2x because the distance is the same on both sides.

Equation gave me result 0 and 2.

x^2-12x+36.36=2x didn't give me the right result.

Any other ideas?