Please, if anyone could solve and explain to me the process of solving these two problems I would be extremely grateful. (It's not about the result, I really need to know HOW to do this, so If I can see a process of solving these problems I hope I will be able to understand it).
1) IF (b-2a)/(4a+3b)=2 (a,b!=0, 4a+3b!=0), THEN (2a^2-3ab+5b^2)/(4a^2+3b^2) EQUALS?
2) Value of the expression (25^(0,3)*5^(0,4))/12^(-1/3) belongs to the interval (which)?
Since I have started writing,
For 1), the advice above is equivalent to expressing b through a from the first equation and substituting it into the second expression.
For 2), does 0,3 mean 3/10 or an interval from 1 to 3? In the English-speaking world, period is most commonly used as a decimal mark. If it means 3/10, then the value of this expression belongs to many intervals. For example, . To get a tighter upper bound, .