Solve for x,y,and z. Q.1 4x - y + 3z = 9 3x + y - z = 5 2x + 3y - 2z = 1 Q.2 2a + 4b + 5c = 2 5a + 3b - 2c = 13 3a - 2b - 3c = 0
If you don't know how to do row reduction, how about substitution?
Take the second equation and solve it for z:
Now insert this value of z into the other two equations:
So we need to solve
Now solve the bottom equation for y:
and insert this value into the top equation:
So we have
or
.
Thus
and
Thus the solution to the system is (x, y, z) = (2, -1, 0).
-Dan