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Math Help - Solving two equations.

  1. #1
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    Solving two equations.

    I have two equations


    v = (pxy)/m

    m = (exy)/c^2

    Does that equal?

    v = (pxy)/((exy)/c^2)

    so will those Ys cancel to give:

     v= (pxe)/c^2

    Thanks.
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  2. #2
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    e^(i*pi)'s Avatar
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    Almost, c^2 needs to be in the numerator and you need to get rid of x in the numerator since it can cancel along with y. e will remain in the denominator

    v = \dfrac{pc^2}{e}

    out of interest is this to do with physics? c^2 tips me off
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  3. #3
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    Yes, its to do with momentum Momentum - Wikipedia, the free encyclopedia

    Your answer is right but still don't know how to get that. Those are not xs but times. Sorry can't use Latex.
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  4. #4
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    Yes, it's to do with momentum Momentum - Wikipedia, the free encyclopedia

    Your answer is right but still don't know how to get that. Those are not xs but times. Sorry can't use Latex.
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  5. #5
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    Quote Originally Posted by mark090480 View Post
    v = (pxy)/m
    m = (exy)/c^2
    Please do NOT use x as multiplication sign!; use *

    p*y / (e*y / c^2)
    = p*y * c^2 / (e*y)
    = c^2 * p*y / (e*y)
    = c^2 * p / e
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