1. ## Remainder Problem

Hi All,
Q If x and y are postive integers and x/y has a remainder of 5, what is the smallest possible value of xy?

1. y > 5 as the dividor has to be larger than the remainder. so let's take 6.
2. The answer goes on to explain 5 as the smallest value of x that can be divided by 6 and leave a remainder of 5. (But 5/6 does not leave a remainder of 5). 11, 17, 23 would though.

Can anyone explain x being 5 to me? Much appreciated.

2. Yes, 5 would be.

5/6 = 0

remainder 5.

It's just like you have 5 people and are requested to make teams of 6 people. How many teams of 6 people would you have and how many people will be left over?

3. Originally Posted by Unknown008
Yes, 5 would be.

5/6 = 0

remainder 5.

It's just like you have 5 people and are requested to make teams of 6 people. How many teams of 6 people would you have and how many people will be left over?

ah yes.. thanks. And the fact the question denotes 'remainder' would suggest you take this approach? Elsewhere 5/6 would equal: .833333.

4. That's what remainder is all about.

Take 11.

11/6 = 1 and remainder 5, but it's also 1.8333

It's the same thing here. It's not a different approach, you just are not used to the quotients being 0 with a remainder.