Q If x and y are postive integers and x/y has a remainder of 5, what is the smallest possible value of xy?
1. y > 5 as the dividor has to be larger than the remainder. so let's take 6.
2. The answer goes on to explain 5 as the smallest value of x that can be divided by 6 and leave a remainder of 5. (But 5/6 does not leave a remainder of 5). 11, 17, 23 would though.
Can anyone explain x being 5 to me? Much appreciated.