I have a unit test tomorrow regarding transformations and conics. I'm working on some problems on transformations regarding the stretches.
Now, the orig formula (or equation) is y=f(x)
then i have to sketch y=1/2f(1/2x)
what can be done to solve this?
i got y -> 2y and x -> 1/2x this means that i can multiply 2 by y coords on orig points and 1/2 by x coords on orig points to find new points of a transformed drawing? Right?
Ok I keep getting wrong answers from my current understanding and my understanding isn't matching the answers on the back page, unfortunately. =\
thanks for your response Soroban but the original points are
(0,0), (1,2), (2,0) (3,-2), (4,0) which i found on the graph, so i came up with the transformation (0,0) (0.5, 4), (1, 0), (1.5, -4), and (2,0)
from my understanding i have to follow this formula
replacing x with bx (x -> bx) is a horiz stretch about the y axis, y=f(bx) describes a horiz stretch
replacing y with (1/a)y, y -> (1/a)y is a vert stretch about the x axis. i.e. (1/a)y=f(x) or y=af(x) is a vert stretch
a>0 is a vert stretch about x axis by a factor of a
a less than 0 is a vert stretch about the x a xis by a factor of |a| and a reflection in the x axis
b > 0 is a horiz stretch about the y axis by a factor of 1/b
b less than 0 is a horiz stretch bout the y axis a by a factor of 1/|b| and a refle in the y-axis
if you want to know, that's the course i'm working on Pure Math 30: Explained!
and i have textbook by me which i copied some of stuff from there to here
I hate myself, I wish I could succeed in this.