I worked it out now.
Thanks.
I put it in the form and worked out p based on the z^2 term and then worked out q based on the p and the z term, and then allowed me to work out what a is.
Thanks.
Hi, I'm stuck on this one. I don't know why though. The answer in the book is 8.
if and , then a is equal to?
A) 4 B) -6 C) 8 D) 6 E) 5
So the first thing I saw was that there is a conjugate zero also so it looks like this
So then I thought i would expand out just the z's, not the z^2s etc. and let them equal the z term in the original expression, -6z
the z cancels out
So then I now have (z - 1 - i)(z - 1 + i)(z - 1) and I will just expand our the constants to get the a
But this doesn't seem to work. I won't bother writing it down because I have done it about 5 times and I can't seem to get the answer. Does anyone know a method to get this one out?
David.