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Math Help - Finding equation of polynomial function

  1. #1
    Junior Member
    Joined
    Feb 2011
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    58

    Finding equation of polynomial function

    From the graph given the zero's are -2, ,-1, 1 and it passes through the point (0,-2)

    I did this:

    x+2, x+1, x-1

    -2 = a(0+2)(0+1)(0-1)
    -2=a(2)(1)(-1)
    -2/-2=a
    1=a

    f(x)=1(x+2)(x+1)(x-1)

    f(x) = x^2+x+2x+2+x^3-x^2+x^2-x+2x^2-2x^2+2x-2

    f(x) = x^3+x^2+4x+0

    However the answer is suppose to be f(x) = x^3 + 2x^2 - x - 2

    Where did I go wrong?
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  2. #2
    Senior Member Sambit's Avatar
    Joined
    Oct 2010
    Posts
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    You made mistake in simplification of (x+2)(x+1)(x-1).
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  3. #3
    Junior Member
    Joined
    Feb 2011
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    O yeh I see where I went wrong. I got the correct answer now. Thanks
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