Originally Posted by

**acc100jt** Consider the following equation,

$\displaystyle x^{2}+\sqrt{x}-2=0$

$\displaystyle (\sqrt{x}+2)(\sqrt{x}-1)=0$

Mr F says: One of the above two lines is wrong because they are not consistent with each other (expand the second line out to see this).

$\displaystyle \sqrt{x}=1$ or $\displaystyle \sqrt{x}=-2$

For the equation $\displaystyle \sqrt{x}=-2$, can I say that there is "no real solution".

Thus $\displaystyle x=1$

My teacher mark me wrong for the part "no real solution", she wrote "wrong reason for rejection".

Can someone please enlighten me? Am I correct?