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Math Help - geometric progression

  1. #1
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    geometric progression

    Three integers are in the ratio 2:3:8. If 4 is added to the middle number, the resulting number is the second term of a geometric progression

    Can anyone please solve this problem?
    thanks in advance
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  2. #2
    rcs
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    isn't that middle term a mean?

    im try:
    2x, 3x, 8x
    let x be the unknown number

    consider m be the mean then 2x/m = m/8x
    m = sq. rt of 16x^2
    m = 4x this is the mean or middle.

    so, 4x + 4 = 3x
    x = - 4 ...
    this substitute...

    hope this is ryt . correct me if i'm wrong.. thanks
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  3. #3
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    4x + 4 = 3x

    It should be 4x = 3x + 4.
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