# Math Help - geometric progression

1. ## geometric progression

Three integers are in the ratio 2:3:8. If 4 is added to the middle number, the resulting number is the second term of a geometric progression

Can anyone please solve this problem?

2. isn't that middle term a mean?

im try:
2x, 3x, 8x
let x be the unknown number

consider m be the mean then 2x/m = m/8x
m = sq. rt of 16x^2
m = 4x this is the mean or middle.

so, 4x + 4 = 3x
x = - 4 ...
this substitute...

hope this is ryt . correct me if i'm wrong.. thanks

3. 4x + 4 = 3x

It should be 4x = 3x + 4.