# find the value of the fraction..

• Mar 2nd 2011, 05:47 PM
rcs
find the value of the fraction..
A given fraction has a value of 3/8. find the value of this fraction, such that when 43 is added to both its numerator and denominator, will result to a new fraction of value 4/9..

can anybody check my work... please

do i have to add 3 + 4 / 8 + 4 = 7/12? what will i do with 4/9? thanks
• Mar 2nd 2011, 06:05 PM
TKHunny
N = Numerator
D = Denominator

$\displaystyle \frac{N}{D} = \frac{3}{8}$

$\displaystyle \frac{N+43}{D+43} = \frac{4}{9}$

Compare this very carefully to the text of the problem statement.
• Mar 2nd 2011, 08:16 PM
rcs
sir/ maam:

where is 43 coming from?
• Mar 2nd 2011, 08:17 PM
topsquark
Quote:

Originally Posted by rcs
sir/ maam:

where is 43 coming from?

Quote:

Originally Posted by rcs
A given fraction has a value of 3/8. find the value of this fraction, such that when 43 is added to both its numerator and denominator, will result to a new fraction of value 4/9..

It comes from the problem statement.

-Dan
• Mar 3rd 2011, 03:44 PM
rcs
i still couldn't figure out the fraction
• Mar 3rd 2011, 05:54 PM
scounged
First, determine what N is in terms of D as follows:
$\displaystyle \frac{N}{D}=\frac{3}{8}\Longrightarrow N=\frac{3D}{8}$
Then you use the other equation to solve for D, and put the fraction $\displaystyle \frac{3D}{8}$ in instead of N, like this:
$\displaystyle \frac{N+43}{D+43}=\frac{4}{9}\Longrightarrow \frac{\frac{3D}{8}+43}{D+43}=\frac{4}{9}$

Then when you have D, you just use the value you get for D to solve for N.