Hi All,

Quite a Simply question but elluding me currently.

I know how 2^4.3^4 = 6^4

But how does 12^5 = 2^10.3^5?

I understand it could also be 2^5.2^6 but I'm trying to determine the above answer?

Thanks In Advance,

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- Mar 2nd 2011, 03:42 AMdumluckExponents
Hi All,

Quite a Simply question but elluding me currently.

I know how 2^4.3^4 = 6^4

But how does 12^5 = 2^10.3^5?

I understand it could also be 2^5.2^6 but I'm trying to determine the above answer?

Thanks In Advance, - Mar 2nd 2011, 03:56 AMPlato
- Mar 2nd 2011, 04:03 AMdumluck
- Mar 2nd 2011, 04:32 AMangypangy
$\displaystyle 27^\frac{1}{3} = \sqrt[3]{27} and you know what 27^4 means. Just split it into parts. It doesn't matter whether you evaluate the fractional part first or the part first $

- Mar 2nd 2011, 04:37 AMPlato
- Mar 2nd 2011, 04:45 AMdumluck
- Mar 2nd 2011, 04:47 AMWilmer
27^4 / 3 or 27^(4/3) ?

- Mar 2nd 2011, 04:51 AMdumluck
- Mar 2nd 2011, 05:49 AMPlato
- Mar 2nd 2011, 06:14 AMdumluck
- Mar 2nd 2011, 06:18 AMPlato
- Mar 2nd 2011, 08:27 AMdumluck
- Mar 2nd 2011, 10:14 AMPlato
- Mar 3rd 2011, 01:56 AMHallsofIvy
Please do

**not**write "3sqrt" for the cube root! The "sq" in "sqrt" is from**square**and the cube root has nothing to do with a square root! For you to say you did NOT mean "$\displaystyle 27^{4/3}$" but meant "(3sqrt(27))^4" is exceptionally confusing.

(Yes, I know that the LaTeX for "cube root" is "\sqrt[3]{}" and I am just as annoyed at that!) - Mar 3rd 2011, 03:57 AMdumluck