Hi Im new to complex numbers and I can't figure out this problem.
(j20)(4 + j0.2)/
4 + j(20 + j0.2)
I'm not sure how how to go about doing this to get an answer of 3.77 + j0.944
Can any one help me?
on the tutorial it shows some of the working.
(j20)(4 + j0.2)/
4 + j(20 + j0.2)
= (j20)(4 + j0.2)/
4 + j20.2
= (j20)(4 + j0.2)(4-j20.2)/
(4 + j20.2)(4 -j20.2)
=(j20)(4 + j0.2)(4-j20.2)/
16 + 20.2^2
then not sure how to work the numerator out
this is 4 steps, the spacings hasnt worked unfortunately.
If you want to use the fixed-width font and consecutive spaces, you can use the [code]...[/code] tags. However, it is better to write the expression in a single line using parentheses.
Is your expression $\displaystyle \displaystyle\frac{(20i)(4 + 0.2i)}{4 + i(20 + 0.2i)}$? Then it is not equal to $\displaystyle \displaystyle\frac{(20i)(4 + 0.2i)}{4 + 20.2i}$.
Hello, suzidoyle635!
I assume the original problem was written in Klingon.
No one on this planet writes like that.
Besides, there are obviously some typos . . .
$\displaystyle \dfrac{j20(4 + j0.2)}{4 + j(20 + j0.2)}$
$\displaystyle \text{Answer: }\:3.77 + j0.944$
$\displaystyle \text{I am }guessing\text{ that the problem is: }\;\dfrac{20i(4+0.2i)}{4 + 20i + 0.2i}$
$\displaystyle \text{This simplifies to: }\;\dfrac{\text{-}4 + 80i}{4+ 20.2i}$
$\displaystyle \displaystyle \text{Rationalize: }\;\frac{\text{-}4+80i}{4+20.2i}\cdot\frac{4=20.2i}{4-20.2i} \;=\;\frac{\text{-}16 + 80.8i + 320i + 1616}{16+ 408.04}$
. . . . . . . . $\displaystyle \displaystyle =\;\frac{1600 + 400.8i}{424.04} \;=\;\frac{1600}{424.04} + \frac{400.8}{424.04}i $
. . . . . . . . $\displaystyle =\;3.773228941 + 0.94519385i $
. . . . . . . . $\displaystyle \approx\;3.77 + 0.945i$