I want to know how to solve this, not just the answer. Thanks.

The ratio of rubies to emeralds was 3 to 1, and the ratio of emeralds to diamonds was 2 to 1. If there were 18 rubies, emeralds, and diamonds in all, how many of each were there?

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- Feb 28th 2011, 04:04 PMwizkid94Proportion Problem Help
I want to know how to solve this, not just the answer. Thanks.

The ratio of rubies to emeralds was 3 to 1, and the ratio of emeralds to diamonds was 2 to 1. If there were 18 rubies, emeralds, and diamonds in all, how many of each were there? - Feb 28th 2011, 04:13 PMQuacky
Ruby:Emerald are in the following ratio:

Can you appreciate that this is equivalent to:

?

So If I have R:E:D, I could write it all in one ratio as:

**Working backwards, for every one diamond, there are two emeralds. And for every emerald, there are three times as many rubies**. This is the core statement.

Now, in the ratio above there are gems. We could say that for every gems, are rubies. So, if that is true, how many rubies would there be in a collection of gems? That is to say, for every gems, would be rubies? Use equivalent fractions to work it out. - Feb 28th 2011, 11:22 PMlanierms
You can also use a constant to figure it out quite easily.

Solution:

Ruby:Emerald = .

So, Ruby = , Emerald = .

Emerald: Diamond = = Diamond.

So, there are 3k rubies, k emeralds and half k diamonds.

Now, if we add all of them,

.

So, there are 12 rubies, 4 emeralds and 2 diamonds.

The solution posted by**Quacky**is great, but I don't think problems will always be simple like this one. - Mar 1st 2011, 07:23 PMwizkid94