Hi all;

I know how to solve fractions with negative exponents

but what happens when there's constant in the numereator

and/or the denominator.

Thanks.

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- Feb 27th 2011, 11:09 AManthonyefractions with negative exponents
Hi all;

I know how to solve fractions with negative exponents

but what happens when there's constant in the numereator

and/or the denominator.

Thanks. - Feb 27th 2011, 11:11 AMArchie Meade
If you post an example that you are stuck on,

it will be much easier to answer specifically.

Then the general cases will be much more obvious. - Feb 27th 2011, 11:17 AManthonye
-15x^-1y^4z^-3 / 45x^-4yz^2 the answer is -x^3y^3 /3x^5

But what I want to know how to solve these type of fractions when there's a constant in the numerator and/or denominator. - Feb 27th 2011, 11:44 AMskeeter
$\displaystyle \dfrac{-15x^{-1}y^4z^{-3}}{45x^{-4}yz^2} = $

$\displaystyle \dfrac{-15}{45} \cdot \dfrac{x^{-1}}{x^{-4}} \cdot \dfrac{y^4}{y} \cdot \dfrac{z^{-3}}{z^2} = $

$\displaystyle \dfrac{-1}{3} \cdot \dfrac{x^3}{1} \cdot \dfrac{y^3}{1} \cdot \dfrac{1}{z^5}$ - Feb 27th 2011, 11:51 AManthonye
Oops that should be 3z^5 in the denominator but how to solve if there was lets say

+whole any number or -whole any number in top or bottom of fraction. - Feb 27th 2011, 01:03 PMskeeter
- Feb 27th 2011, 01:12 PMArchie Meade
There is a constant in both the numerator and denominator in that example.

However, all terms in both the numerator and denominator are multiplied, so they are all factors.

Do you mean if you had terms combined by addition or subtraction instead of multiplication?

Then you try to factorise if possible.

If you are more specific,

someone can help you with an another example, if you post one. - Feb 27th 2011, 01:28 PManthonye
Yes I do mean if the terms are combined with + - operators after the multiplication terms.

lets say I had +3 at the end. - Feb 27th 2011, 01:30 PMskeeter
- Feb 27th 2011, 01:47 PManthonye
I havent got one to show you.

- Feb 27th 2011, 01:54 PMArchie Meade
Ok then.

- Feb 27th 2011, 01:58 PManthonye
Just say at the end of the original numerator it had +3.

- Feb 27th 2011, 02:02 PMArchie Meade
- Feb 27th 2011, 02:05 PMskeeter
- Feb 27th 2011, 02:13 PManthonye
Yes of course you would just didn't think.

I'll have a better look tomorrow going to bed work in morning.

Thanks again.