(16e^x) - (16e^2x) = 3 and the answer says that x = 0.25 but i can't see how you can get there? please help, much appreciated!! thanks!
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Rewrite it as . Now let so that the equation becomes , which is a quadratic equation you can solve for , and then solve for .
Originally Posted by Yehia (16e^x) - (16e^2x) = 3 and the answer says that x = 0.25 but i can't see how you can get there? please help, much appreciated!! thanks! Have you correctly quoted the problem?
Originally Posted by Prove It Rewrite it as . Now let so that the equation becomes , which is a quadratic equation you can solve for , and then solve for . thanks
Last edited by Yehia; Feb 25th 2011 at 06:21 AM.
Originally Posted by Yehia (16e^x) - (16e^2x) = 3 and the answer says that x = 0.25 but i can't see how you can get there? please help, much appreciated!! thanks! Thank you very much for answering to my previous question. Please, post your work if you get some of this (i) is a solution of the given equation. (ii) The equation has only one solution.
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