(16e^x) - (16e^2x) = 3

and the answer says that x = 0.25 but i can't see how you can get there? please help, much appreciated!! thanks!

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- Feb 25th 2011, 03:23 AMYehiaHow to solve this simple exponential equation?
(16e^x) - (16e^2x) = 3

and the answer says that x = 0.25 but i can't see how you can get there? please help, much appreciated!! thanks! - Feb 25th 2011, 03:27 AMProve It
Rewrite it as $\displaystyle \displaystyle 0 = 16e^{2x} - 16e^x + 3$

$\displaystyle \displaystyle 0 = 16\left(e^x\right)^2 - 16e^x + 3$.

Now let $\displaystyle \displaystyle X = e^x$ so that the equation becomes

$\displaystyle \displaystyle 0 = 16X^2 - 16X + 3$, which is a quadratic equation you can solve for $\displaystyle \displaystyle X$, and then solve for $\displaystyle \displaystyle x$. - Feb 25th 2011, 03:32 AMFernandoRevilla
- Feb 25th 2011, 04:27 AMYehia
- Feb 25th 2011, 05:14 AMFernandoRevilla