1. ## Closed

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Factorise ac-3+3x-a
Is there a possible solution for this?

Thanks

2. There is no factor common to the who equation but you can factor into two terms

$\displaystyle a(c-1) - 3(1-x)$

3. If you meant $\displaystyle \displaystyle ac - 3 + 3c - a$

$\displaystyle \displaystyle = ac - a + 3c - 3$

$\displaystyle \displaystyle = a(c - 1) + 3(c - 1)$

$\displaystyle \displaystyle = (c-1)(a+3)$.

4. Originally Posted by Prove It
If you meant $\displaystyle \displaystyle ac - 3 + 3c - a$

$\displaystyle \displaystyle = ac - a + 3c - 3$

$\displaystyle \displaystyle = a(c - 1) + 3(c - 1)$

$\displaystyle \displaystyle = (c-1)(a+3)$.
Originally Posted by e^(i*pi)
There is no factor common to the who equation but you can factor into two terms

$\displaystyle a(c-1) - 3(1-x)$
Thanks guys, ima go clarify this question with my teacher tomorrow, maybe the question is "bugged"