Thread Closed ------------------------------------------------------------------ Factorise ac-3+3x-a Is there a possible solution for this? Thanks
Last edited by FailInMaths; Feb 24th 2011 at 02:17 AM.
Follow Math Help Forum on Facebook and Google+
There is no factor common to the who equation but you can factor into two terms $\displaystyle a(c-1) - 3(1-x)$
If you meant $\displaystyle \displaystyle ac - 3 + 3c - a$ $\displaystyle \displaystyle = ac - a + 3c - 3$ $\displaystyle \displaystyle = a(c - 1) + 3(c - 1)$ $\displaystyle \displaystyle = (c-1)(a+3)$.
Originally Posted by Prove It If you meant $\displaystyle \displaystyle ac - 3 + 3c - a$ $\displaystyle \displaystyle = ac - a + 3c - 3$ $\displaystyle \displaystyle = a(c - 1) + 3(c - 1)$ $\displaystyle \displaystyle = (c-1)(a+3)$. Originally Posted by e^(i*pi) There is no factor common to the who equation but you can factor into two terms $\displaystyle a(c-1) - 3(1-x)$ Thanks guys, ima go clarify this question with my teacher tomorrow, maybe the question is "bugged" Thread Closed =) *Thanked