# Thread: Point Slope Form help

1. ## Point Slope Form help

I am having an issue understanding this question, "Find and equation of the line with the given point & slope
1. ( 3x, 2y) m = 2
y= mx + b

2y = 2 (3x) + B
Then
2y = 6x + b
Then
Divide 2y by 2, then you would have 6/2 x + b
y = 3x + b

I cant figure out if thats the answer or what.

I have the same situation with this problem

(3r , 3s) m = 1

2. You can say $\displaystyle \displaystyle b = 2y-6x$

so in $\displaystyle \displaystyle y = mx+b \implies y= 2x+(2y-6x)$ finish from here.

3. ## point slope formula

Hello rush115etc,

the point slope formula y-2 / x-3 = 2

y-2 = 2(x-3) y -2=2x -6 y=2x-4

bjh

4. Originally Posted by Rush21125150
I am having an issue understanding this question, "Find and equation of the line with the given point & slope
1. ( 3x, 2y) m = 2
Did the problem really say that? (3x, 2y) is NOT a point. (3, 2) is a point.
2= 2(3)+ b
b= 2- 6= -4,
y= 2x- 4 has slope 2 and passes through the point (3, 2).

y= mx + b

2y = 2 (3x) + B
Then
2y = 6x + b
Then
Divide 2y by 2, then you would have 6/2 x + b
y = 3x + b

I cant figure out if thats the answer or what.

I have the same situation with this problem

(3r , 3s) m = 1
I don't like that notation! I think that is just telling you to use (r, s) rather than (x,y) as your variables. That is, s= mr+ B with r= 3 and s= 3 rather than y= mx+ b with x= 3r and y= 3s. You are looking for an equation of the form s= (1)r+ b that satisfies 3= 3+ b. Of course that gives b= 0 so s= r is the equation.