You can say
so in finish from here.
I am having an issue understanding this question, "Find and equation of the line with the given point & slope
1. ( 3x, 2y) m = 2
y= mx + b
2y = 2 (3x) + B
Then
2y = 6x + b
Then
Divide 2y by 2, then you would have 6/2 x + b
y = 3x + b
I cant figure out if thats the answer or what.
I have the same situation with this problem
(3r , 3s) m = 1
Did the problem really say that? (3x, 2y) is NOT a point. (3, 2) is a point.
2= 2(3)+ b
b= 2- 6= -4,
y= 2x- 4 has slope 2 and passes through the point (3, 2).
I don't like that notation! I think that is just telling you to use (r, s) rather than (x,y) as your variables. That is, s= mr+ B with r= 3 and s= 3 rather than y= mx+ b with x= 3r and y= 3s. You are looking for an equation of the form s= (1)r+ b that satisfies 3= 3+ b. Of course that gives b= 0 so s= r is the equation.y= mx + b
2y = 2 (3x) + B
Then
2y = 6x + b
Then
Divide 2y by 2, then you would have 6/2 x + b
y = 3x + b
I cant figure out if thats the answer or what.
I have the same situation with this problem
(3r , 3s) m = 1