here is my problem

**sweetkitten** · February 21st 2011, 08:36 AM

3(x+y)=z

will you help me solve it

its very frustrating

solve for y

**Plato** · February 21st 2011, 08:37 AM

Originally Posted by sweetkitten

3(x+y)=z
will you help me solve it

What do you mean solve?
Solve for what?

**e^(i*pi)** · February 21st 2011, 08:38 AM

Solve for what? There are 3 unknowns in one equation so this can only be solved for one variable in terms of the two others.

For example $x = \dfrac{z-3y}{3}$

**sweetkitten** · February 21st 2011, 08:40 AM

solve for y sorry

**e^(i*pi)** · February 21st 2011, 09:23 AM

If you divide both sides by 3 you get $x+y = \dfrac{z}{3}$

**sweetkitten** · February 21st 2011, 09:25 AM

Originally Posted by e^(i*pi)

If you divide both sides by 3 you get $x+y = \dfrac{z}{3}$

but i need to solve for y
if i subtracted x would i be solving for y????????????????
because then the equation would be
y=z/3-x
i think

**e^(i*pi)** · February 21st 2011, 10:18 AM

Yes that's right, I was just helping you en route

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