# Thread: here is my problem

1. ## here is my problem

3(x+y)=z

will you help me solve it

its very frustrating
solve for y

2. Originally Posted by sweetkitten
3(x+y)=z
will you help me solve it
What do you mean solve?
Solve for what?

3. Solve for what? There are 3 unknowns in one equation so this can only be solved for one variable in terms of the two others.

For example $\displaystyle x = \dfrac{z-3y}{3}$

4. solve for y sorry

5. If you divide both sides by 3 you get $\displaystyle x+y = \dfrac{z}{3}$

6. Originally Posted by e^(i*pi)
If you divide both sides by 3 you get $\displaystyle x+y = \dfrac{z}{3}$
but i need to solve for y
if i subtracted x would i be solving for y????????????????
because then the equation would be
y=z/3-x
i think

7. Yes that's right, I was just helping you en route