Thread: linear inequalities ..checking answer

hi-
i have to slove this problem

-3/2x > -6

what i did was i multiply 2 to -3/2 and -6
i cancel the 2 and i got -12

so i am left with -3x>-12
i then divide -3 to both sides. and i got

4>x
is this correct?

thanks

Originally Posted by Candy101

hi-
i have to slove this problem

-3/2x > -6

what i did was i multiply 2 to -3/2 and -6
i cancel the 2 and i got -12

so i am left with -3x>-12
i then divide -3 to both sides. and i got

4>x
is this correct?

thanks

yes, x < 4

Am I suppose to change the sign from > to < becuase I divided by a negative number? So the
answer will be x<4?

No, you did that when you swapped the sides!

You had -3x> -12. If you had simply divided both sides by -3 without either changing the sign or swapping sides you would have x> 4 which would be wrong. You can either change the sign, to get x< 4 or swap sides to get 4> x (your answer) but not both.

Of course, it is easy to check this yourself. A number less than 4 is 2. Does x= 2 satisfy (-3/2)x> -6?