hi-

i have to slove this problem

-3/2x > -6

what i did was i multiply 2 to -3/2 and -6

i cancel the 2 and i got -12

so i am left with -3x>-12

i then divide -3 to both sides. and i got

4>x

is this correct?

thanks

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- Feb 20th 2011, 06:56 PMCandy101linear inequalities ..checking answer
hi-

i have to slove this problem

-3/2x > -6

what i did was i multiply 2 to -3/2 and -6

i cancel the 2 and i got -12

so i am left with -3x>-12

i then divide -3 to both sides. and i got

4>x

is this correct?

thanks - Feb 20th 2011, 06:59 PMskeeter
- Feb 20th 2011, 09:13 PMCandy101
Am I suppose to change the sign from > to < becuase I divided by a negative number? So the

answer will be x<4? - Feb 21st 2011, 03:23 AMHallsofIvy
No, you did that when you swapped the sides!

You had -3x> -12. If you had simply divided both sides by -3 without either changing the sign or swapping sides you would have x> 4 which would be wrong. You can**either**change the sign, to get x< 4**or**swap sides to get 4> x (your answer) but not both.

Of course, it is easy to check this yourself. A number less than 4 is 2. Does x= 2 satisfy (-3/2)x> -6?