(3a+7)/(a+4) >= 0
I forgot the step to solve the problem , please help me !!!
Look at the numerator and the denominator.
If both have the same sign then the inequality is true.
It is easy to see that if $\displaystyle a<-4$ then both are negative.
If $\displaystyle a\ge -\frac{7}{3}$ then both are non-negative.
Write the solution set as $\displaystyle (-\infty,-4)\cup\left[-\frac{7}{3},\infty\right)$.
There is no complicated calculation necessary.