(k-4)/(K^2+5K+6) * (k^2+8K+12)/(K^2-10K+24)
You can factor all those expressions to make life simpler
$\displaystyle \dfrac{(k-4)}{(k+3)(k+2)} \cdot \dfrac{(k+6)(k+2)}{(k-6)(k-4)}$
As long as $\displaystyle k \neq -2, -3, 4, 6$ you can do some cancelling
That is not an equation but a rational fraction. To simplify, decompose the second degree polynomials, for example $\displaystyle k^2-10k+24=(k-4)(k-6)$ .
Fernando Revilla
Edited: Sorry, I didn`t see e^(i*pi)'s post.