Simplify the below equation

**hoanghai549** · February 19th 2011, 08:13 AM

(k-4)/(K^2+5K+6) * (k^2+8K+12)/(K^2-10K+24)

**e^(i*pi)** · February 19th 2011, 08:18 AM

You can factor all those expressions to make life simpler

$\dfrac{(k-4)}{(k+3)(k+2)} \cdot \dfrac{(k+6)(k+2)}{(k-6)(k-4)}$

As long as $k \neq -2, -3, 4, 6$ you can do some cancelling

**FernandoRevilla** · February 19th 2011, 08:22 AM

Deleted by repetition.

**FernandoRevilla** · February 19th 2011, 08:23 AM

That is not an equation but a rational fraction. To simplify, decompose the second degree polynomials, for example $k^2-10k+24=(k-4)(k-6)$ .

Fernando Revilla

Edited: Sorry, I didn`t see e^(i*pi)'s post.

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