(k-4)/(K^2+5K+6) * (k^2+8K+12)/(K^2-10K+24)

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- Feb 19th 2011, 08:13 AMhoanghai549Simplify the below equation
(k-4)/(K^2+5K+6) * (k^2+8K+12)/(K^2-10K+24)

- Feb 19th 2011, 08:18 AMe^(i*pi)
You can factor all those expressions to make life simpler

$\displaystyle \dfrac{(k-4)}{(k+3)(k+2)} \cdot \dfrac{(k+6)(k+2)}{(k-6)(k-4)}$

As long as $\displaystyle k \neq -2, -3, 4, 6$ you can do some cancelling - Feb 19th 2011, 08:22 AMFernandoRevilla
Deleted by repetition.

- Feb 19th 2011, 08:23 AMFernandoRevilla
That is not an equation but a rational fraction. To simplify, decompose the second degree polynomials, for example $\displaystyle k^2-10k+24=(k-4)(k-6)$ .

Fernando Revilla

Edited: Sorry, I didn`t see**e^(i*pi)**'s post.