Thread: hard fraction!

Originally Posted by harish21

No it does not. You are subtracting x and 1 from both sides of the equation.



subtract 1 from both the sides:



that leaves you with:



now you subtract x from both the sides. this gives you:



which gives you:



therefore

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Note:

In the first box, you are subtracting x from -5x. In the second box, you are adding x to -5x. This is where your confusion lies.

If you still dont understand it, please refer to your books/notes/instructor to avoid trouble in the future.




Please refer to post Number 2 by Unknown008

your question was

then Unknown008's method (which you've been told multiple number of times) takes you :



multiplying both sides of this equation by .gives you:

.

Have fun!

okay i think i get it now, so would 0=6x^2 -6x be the answer?

Does your question tell you to find the value of x?

usually with questions like these i usually just find X via quadratic equation or by dividing a number by the amount of X's.

how would i work out x with this question?

You have:



Find x from here..

would i square root 6x^2=6
0=6-6

plus 1 to each side to get:
6=6
6/6=1
x=1?

Originally Posted by andyboy179

would i square root 6x^2=6
0=6-6

plus 1 to each side to get:
6=6
6/6=1
x=1?

No, to find all answers, write as a multiplication of factors...







6x is common to both, so factor...



6 is not 0, so

Those factors now tell you the answers because any multiple of zero is zero.

Yes, x = 1 but you forgot 0

If you so much want to use the formula, you can make this:





Here, you have

So, a = 6, b = -6, c = 0

So by doing the quadratic equation I would end with the answers of 1 and 0 for x??

Did you get something else than 1 and 0?

No I did the quadratic and get 1 and 0.
To get it I did:
X=6+ (square root)36-4x6x0/12=1
X=6- (square root)36-4x6x0/12=0