2 / 5 / x + 4

Having trouble solving this problem and have no clue where to start. I'm trying to eliminate any fractions in the denominator.

Couln't figure out how to format this right so I just have it typed out. It's 2 divided by 5 over x + 4

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- Feb 15th 2011, 02:47 PMstreet1030Complex Fractions with variable in denominator
2 / 5 / x + 4

Having trouble solving this problem and have no clue where to start. I'm trying to eliminate any fractions in the denominator.

Couln't figure out how to format this right so I just have it typed out. It's 2 divided by 5 over x + 4 - Feb 15th 2011, 02:51 PMe^(i*pi)
Use \dfrac for a fraction:

However, I see no imaginary part and hence no complex number here. That form is the simplest it's going to get since you can't eliminate x from the denominator.

What are you hoping to achieve?

EDIT:

Assuming you mean then recall that dividing by a fraction is the same as flipping and multiplying it. Thus which has no x in the denominator. - Feb 15th 2011, 02:51 PMtopsquark
- Feb 15th 2011, 02:53 PMPlato
- Feb 15th 2011, 02:58 PMstreet1030
Sorry for the confusion guys. Forgot to preview post before posting. It's supposed to be all over

- Feb 15th 2011, 03:07 PMe^(i*pi)
That would be Plato's answer then and if you're wondering he/she has "dropped" the 5 into the denominator and then distributed it

- Feb 15th 2011, 03:11 PMstreet1030
Having trouble understanding how we went from

to Platos

Did you cross multiply to cancel out the x + 4 in the denominator and the numerator. Then just distribute the 5 to the remaining x + 4? - Feb 15th 2011, 03:20 PMPlato
- Feb 15th 2011, 03:24 PMstreet1030
Alright thanks guys! Going to go test this out on some more problems.

- Feb 15th 2011, 03:32 PMtopsquark
- Feb 15th 2011, 03:40 PMstreet1030
O yeah. I need to do the one you're doing topsquark. So the way you did it. you get? 2x + 8 / 5?

- Feb 15th 2011, 04:03 PMtopsquark
- Feb 15th 2011, 04:12 PMstreet1030
Thanks a bunch :D