Re-arrange in terms of P: $\displaystyle P = x + SPT / 100$ Thank you.
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What are you solving for? P?
Originally Posted by Ackbeet What are you solving for? P? Yes.
Ok, so what's the usual first step? Or what have you done so far?
$\displaystyle P - SPT/100 = x$ P.S. I don't need a worked solution- but I do need to re-arranged pretty quickly (it's not school work).
That's correct. What's next?
I don't know. That's why I'm here.
Originally Posted by rome I don't know. That's why I'm here. That's fine. That's why we're here, as well: to help you get unstuck. Try factoring the P out. What do you get next?
Like this? $\displaystyle P - P(ST/100) = x$
Well, that's certainly not incorrect, but can't you factor even more?
How do you mean? Surely P-P=0 ?
No, I was thinking more like this: $\displaystyle P - P(ST/100) = x$ $\displaystyle P(1- ST/100) = x.$ That's because of the distributive law. Do you see how that's done?
Edit: posted this before I saw your post Hold on, like this: $\displaystyle P - PST(0.01) = x$ ?
Originally Posted by Ackbeet No, I was thinking more like this: $\displaystyle P - P(ST/100) = x$ $\displaystyle P(1- ST/100) = x.$ That's because of the distributive law. Do you see how that's done? I think so. Thank you.
Can you finish? What condition do you think you'll need to mention as a caveat?
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