Re-arrange in terms of P:

Thank you.

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- February 15th 2011, 11:51 AMromeRe-arrange
Re-arrange in terms of P:

Thank you. - February 15th 2011, 12:14 PMAckbeet
What are you solving for? P?

- February 15th 2011, 12:29 PMrome
- February 15th 2011, 12:30 PMAckbeet
Ok, so what's the usual first step? Or what have you done so far?

- February 15th 2011, 12:35 PMrome

P.S. I don't need a worked solution- but I do need to re-arranged pretty quickly (it's not school work). - February 15th 2011, 12:37 PMAckbeet
That's correct. What's next?

- February 15th 2011, 12:41 PMrome
I don't know. That's why I'm here.

- February 15th 2011, 12:43 PMAckbeet
- February 15th 2011, 12:46 PMrome
Like this?

- February 15th 2011, 12:47 PMAckbeet
Well, that's certainly not incorrect, but can't you factor even more?

- February 15th 2011, 12:49 PMrome
How do you mean? Surely P-P=0 ?

- February 15th 2011, 12:52 PMAckbeet
No, I was thinking more like this:

That's because of the distributive law. Do you see how that's done? - February 15th 2011, 12:53 PMrome
Edit: posted this before I saw your post

Hold on, like this:

? - February 15th 2011, 12:58 PMrome
- February 15th 2011, 01:00 PMAckbeet
Can you finish? What condition do you think you'll need to mention as a caveat?