I have no idea how to do these. Help would be nice. 3√27x^6y^9 5√8a^7c^11
Last edited by mr fantastic; Feb 13th 2011 at 04:28 PM. Reason: Re-titled.
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You want to graph these? Is the first equation $\displaystyle \displystyle \sqrt[3]{27}x^6y^9$ or $\displaystyle \displyatyle 3\sqrt{27}x^6y^9$ ?
Last edited by pickslides; Feb 13th 2011 at 03:59 PM.
Sorry i didnt clarify. It says to simplify them. both problems are written like the first example you typed.(little 3). then the second problem has a (little 5) outside the root symbol.
$\displaystyle \displaystyle \sqrt[3]{27} = 3 $ as $\displaystyle \dispalystyle 3^3 = 27 $ Does this make sense?
yes? =) im sorry i seem so unbright...im not that great in mathematics.
I'm starting to think your equation is $\displaystyle \displaystyle \sqrt[3]{27x^6y^9}$ ?
yes sir..thats what my homework paper says..i just have to simplify it...and i dont know how to do that.
Firstly \$\displaystyle \displaystyle \sqrt[3]{27x^6y^9} = \sqrt[3]{27}\times \sqrt[3]{x^6}\times \sqrt[3]{y^9}$ Now recall that $\displaystyle \displaystyle \sqrt[n]{a} = a^{\frac{1}{n}}$ Re-write the equation using this rule.
mk. thnks
I get $\displaystyle \displaystyle \sqrt[3]{27}\times \sqrt[3]{x^6}\times \sqrt[3]{y^9} = 27^{\frac{1}{3}}x^{6\times {\frac{1}{3}}}\times y^{9\times {\frac{1}{3}}}$ Simplify this..
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