Results 1 to 10 of 10

Math Help - Simplify surds and powers.

  1. #1
    Newbie
    Joined
    Jan 2011
    Posts
    7

    Simplify surds and powers.

    I have no idea how to do these. Help would be nice.

    3√27x^6y^9


    5√8a^7c^11
    Last edited by mr fantastic; February 13th 2011 at 04:28 PM. Reason: Re-titled.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    You want to graph these?

    Is the first equation \displystyle \sqrt[3]{27}x^6y^9 or \displyatyle 3\sqrt{27}x^6y^9 ?
    Last edited by pickslides; February 13th 2011 at 03:59 PM.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jan 2011
    Posts
    7
    Sorry i didnt clarify. It says to simplify them.

    both problems are written like the first example you typed.(little 3).
    then the second problem has a (little 5) outside the root symbol.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    \displaystyle \sqrt[3]{27} = 3 as \dispalystyle  3^3 = 27

    Does this make sense?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Jan 2011
    Posts
    7
    yes? =) im sorry i seem so unbright...im not that great in mathematics.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    I'm starting to think your equation is \displaystyle \sqrt[3]{27x^6y^9} ?
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    Jan 2011
    Posts
    7
    yes sir..thats what my homework paper says..i just have to simplify it...and i dont know how to do that.
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    Firstly \ \displaystyle \sqrt[3]{27x^6y^9} = \sqrt[3]{27}\times \sqrt[3]{x^6}\times \sqrt[3]{y^9}

    Now recall that \displaystyle \sqrt[n]{a} = a^{\frac{1}{n}}


    Re-write the equation using this rule.
    Follow Math Help Forum on Facebook and Google+

  9. #9
    Newbie
    Joined
    Jan 2011
    Posts
    7
    mk. thnks
    Follow Math Help Forum on Facebook and Google+

  10. #10
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    I get \displaystyle  \sqrt[3]{27}\times \sqrt[3]{x^6}\times \sqrt[3]{y^9} = 27^{\frac{1}{3}}x^{6\times {\frac{1}{3}}}\times y^{9\times {\frac{1}{3}}}

    Simplify this..
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: August 31st 2011, 03:32 AM
  2. Misc. questions on powers and surds.
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 26th 2011, 06:16 AM
  3. Lowering Powers - Simplify in terms of cosine
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: November 12th 2009, 04:33 PM
  4. How to simplify a quotiŽnt with powers?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 1st 2009, 05:26 AM
  5. Powers inside roots? [surds]
    Posted in the Math Topics Forum
    Replies: 3
    Last Post: February 5th 2009, 01:53 AM

Search Tags


/mathhelpforum @mathhelpforum