1. stuck

solve: 2/3 + 4/6 = ____.

Am i doing this right ?

2 x 2 = 4
- = -
3 x 3 = 6 4 x 1 = 4
- = -
6 x 1 = 6

= 8/6 << how do i put in simplest term ???

2. Originally Posted by misz infamouz

solve: 2/3 + 4/6 = ____.

Am i doing this right ?

2 4
- = -
3 6 = 8/6 << how do i put in simplest term ???
4 4
- = -
6 6
yes, the answer is 8/6. to get it in the simplest form, divide the top and bottom by 2, you get 4/3

3. Originally Posted by Jhevon
yes, the answer is 8/6. to get it in the simplest form, divide the top and bottom by 2, you get 4/3
I simplified it and got 2/1.
But isn't that incorrect ?
Because doesn't the bottom denominator have to be lower
than the top denominator ?

4. Originally Posted by misz infamouz
I simplified it and got 2/1.
But isn't that incorrect ?
Because doesn't the bottom denominator have to be lower
than the top denominator ?

as i said, the answer is 4/3, if you want a proper fraction, we can rewrite this as 1 1/3

5. Originally Posted by Jhevon
as i said, the answer is 4/3, if you want a proper fraction, we can rewrite this as 1 1/3
Pet peeve warning! Danger! Danger Will Robinson!
[rant]
Just for the record here, I dislike proper fractions.

It's not the concept, it's the form of the number. Something like "1 1/3" is likely to be misconstrued either as 11/3 or 1 times 1/3. The only saving grace to them is when it is typed in some sort of font such as $\displaystyle 1 \frac{1}{3}$, but this also can be taken to be $\displaystyle 1 \cdot \frac{1}{3} = \frac{1}{3}$.

I think overall it's much better just to leave it as 4/3.
[/rant]

-Dan

6. Originally Posted by topsquark
Pet peeve warning! Danger! Danger Will Robinson!
[rant]
Just for the record here, I dislike proper fractions.

It's not the concept, it's the form of the number. Something like "1 1/3" is likely to be misconstrued either as 11/3 or 1 times 1/3. The only saving grace to them is when it is typed in some sort of font such as $\displaystyle 1 \frac{1}{3}$, but this also can be taken to be $\displaystyle 1 \cdot \frac{1}{3} = \frac{1}{3}$.

I think overall it's much better just to leave it as 4/3.
[/rant]

-Dan
I 100% agree with you! I would have left it like that had the poster not had a problem with it

7. Originally Posted by misz infamouz

solve: 2/3 + 4/6 = ____.

Am i doing this right ?

2 x 2 = 4
- = -
3 x 3 = 6 4 x 1 = 4
- = -
6 x 1 = 6

= 8/6 << how do i put in simplest term ???
yes your doing correct way.now the denominators are same.adding the nuemarators.so that 8+4=12 and 12/6=2 is the answer.

8. 3 x 3 = 6 is definitely not true.

9. Originally Posted by misz infamouz

solve: 2/3 + 4/6 = ____.

Am i doing this right ?

2 x 2 = 4
- = -
3 x 3 = 6 4 x 1 = 4
- = -
6 x 1 = 6

= 8/6 << how do i put in simplest term ???
sorry for yesterdays answer.here 3*3=9but not 6.what you have todo is numaretor and denominator is multiplied with same number and that must be3*2=6and2*2=4.now that will become 4/6+4/6=8/6 this cancacel with 2 then you will get 4/3. that is the answer.

10. Originally Posted by asurekha1970
sorry for yesterdays answer.here 3*3=9but not 6.what you have todo is numaretor and denominator is multiplied with same number and that must be3*2=6and2*2=4.now that will become 4/6+4/6=8/6 this cancacel with 2 then you will get 4/3. that is the answer.

11. Yes asurekha1970, there is no need to reply to questions that are already answered unless you see a mistake with the answer, or if you have an easier or completely different method of calculating it.

12. Originally Posted by janvdl
Yes asurekha1970, there is no need to reply to questions that are already answered unless you see a mistake with the answer, or if you have an easier or completely different method of calculating it.
but how can i find new problems.what is the use of joining math forum help.where do i get problems.give answers to my questions.then give advices to me.iam new to this forum.please help me. i want to become a online tutor.

13. Originally Posted by asurekha1970
but how can i find new problems.what is the use of joining math forum help.where do i get problems.give answers to my questions.then give advices to me.iam new to this forum.please help me. i want to become a online tutor.
You have to wait for a problem to spring up. And yes that does take time, but that's the way it is. I think the Americans have started with school and university again, so there will be plenty of problems again soon. There are times when it gets very busy on the forum. Just be patient.

By the way do you have a degree in mathematics?