• February 12th 2011, 04:47 AM
FailInMaths

Question: Factorise 121 - (p+2)Square

Don't know whether if it is (p+39)(p-3) or (p+13)(p-9 or maybe i am wrong
Thanks a lot
• February 12th 2011, 04:51 AM
skeeter
Quote:

Originally Posted by FailInMaths

Question: Factorise 121 - (p+2)Square

Don't know whether if it is (p+39)(p-3) or (p+13)(p-9 or maybe i am wrong
Thanks a lot

$11^2 - (p+2)^2 = [11 - (p+2)][11 + (p+2)] = (9-p)(13+p)$
• February 12th 2011, 05:51 AM
Calye
Remember the difference of 2 squares formula.
That a2-b2=(a+b)(a-b)

P.S. @skeeter how do you type the square of the numeral.
• February 12th 2011, 05:53 AM
Prove It
In math tags you type ^{}, e.g. 3^{25} gives $\displaystyle 3^{25}$.
• February 12th 2011, 05:56 AM
bugatti79
Quote:

Originally Posted by Calye
Remember the difference of 2 squares formula.
That a2-b2=(a+b)(a-b)

P.S. @skeeter how do you type the square of the numeral.

Double click on the equation and you will see the code required to write. To answer your question... x to be squared would be (double click to see the code)

$x^2$