Number formed from different number of digits.

**bahadarali** · February 10th 2011, 10:47 PM

Q27: The sum of all possible two digit number formed from three different
one digit natural number when divided by the sum of the original three
number is equal to:?
A. 18
B. 22
C. 36
D. None of these
how....................?

**tonio** · February 11th 2011, 03:52 AM

Originally Posted by bahadarali

Q27: The sum of all possible two digit number formed from three different
one digit natural number when divided by the sum of the original three
number is equal to:?
A. 18
B. 22
C. 36
D. None of these
how....................?

Let $a,b,c$ be three different digits, so the sum of the different 2-digit numbers formed with them is:

$(a\times 10 + b)+(b\times 10 + a)+(a\times 10 + c)+(c\times 10 + a)+(b\times 10 + c)+(c\times 10 + b)=$

$=2(a+b+c)(10+1)=$ ...so the answer is B.

Tonio

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