Q27: The sum of all possible two digit number formed from three different
one digit natural number when divided by the sum of the original three
number is equal to:?
A. 18
B. 22
C. 36
D. None of these
how....................?

Originally Posted by bahadarali

Q27: The sum of all possible two digit number formed from three different
one digit natural number when divided by the sum of the original three
number is equal to:?
A. 18
B. 22
C. 36
D. None of these
how....................?

Let $\displaystyle a,b,c$ be three different digits, so the sum of the different 2-digit numbers formed with them is:

$\displaystyle (a\times 10 + b)+(b\times 10 + a)+(a\times 10 + c)+(c\times 10 + a)+(b\times 10 + c)+(c\times 10 + b)=$

$\displaystyle =2(a+b+c)(10+1)=$...so the answer is B.

Tonio