Please help!

A service station has 2 kinds of oil, one selling for $1.27/litre and the other for $1.18/litre. How many litres of each must be used to make 90 litres of a mixture that can be sold for $1.24/litre?

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- Jul 21st 2007, 12:01 AM #1

- Jul 21st 2007, 12:08 AM #2

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- Jul 21st 2007, 12:13 AM #3
Hello,

let x be the amount of oil which is sold for $1.27

then (90-x) is the amount of oil which is sold for $1.18.

Now you can set up the equation:

. Expand the bracket and collect like terms :

. Divide both sides of the equation by 0.09 and you'll get:

That means: Take 60 ltrs of the $1.27-oil and 30 ltrs of the $1.18-oil to get the mixture which you can sell for $1.24